The number of real solutions of the equation, $x^{2} - | x | - 12 = 0$ is

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2$
Given: $x^{2} - | x | - 12 = 0$
$\Rightarrow x^{2} - 4 | x | + 3 | x | - 12 = 0$
$\Rightarrow (| x | - 4) (| x | + 3) = 0$
$\Rightarrow | x | = 4$ or $| x | = - 3$ (rejected)
$\Rightarrow x = \pm 4$
$∴$ Number of solutions $= 2$

Suggest Corrections

Similar questions

0 = - 3 + x - x^{2}

The number of real solutions of the equation $x^{2} + 3 | x | + 2$ =0 is:

{(\frac{9}{10})}^{x} = - 3 + x - x^{2}

∣ x^{2} - x - 6 ∣= x + 2

x

x^{2} + {(\frac{x}{x - 1})}^{2} = 8

Join BYJU'S Learning Program