Question

The number of real solutions of $x-\frac{1}{x^2-4}=2-\frac{1}{x^2-4}$ is-

• A. $0$
• B. $1$
• C. $2$
• D. $\infty$

Answer 1

The correct option is A $0$

$x-\frac{1}{x^2-4}=2-\frac{1}{x^2-4}$

we can omit $\frac{1}{x^2-4}$ from both sides provided $x$ not equal to $2$ or $-2$

$x=2$ but as $x\ne 2or-2$

$\therefore norealsolutions$