Question

The number of real tangent from the point $(2,2)$ to the circle $x^2+y^2-6x-4y+3=0$ be

• A. $0$
• B. $1$
• C. $2$
• D. $3$

Answer 1

Answer: (A)

$0$

Before finding the number of tangents from the point $(2,2)$ to the circle

$x^2+y^2-6x-4y+3=0$.......(1), let us check whether the point lies inside or outside or on the circle.

Now

$2^2+2^2-12-8+3=-9<0$

This gives the given point lies inside the given circle.

So no tangent is possible.