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Question

The number of real values of a satisfying the equation a22a sinx+1=0 is


A

Zero

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B

One

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C

Two

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D

Inifnite

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Solution

The correct option is C

Two


Given equations a22asinx+1=0

a=2sinx±24sin2x42 = sinx±2(1sin2x)

a=sinx±icosx

If x=π2 a=1, x=270o a=-1.


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