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Question

The number of real values of x satisfying ∣∣ ∣∣x3x+22x−12x−14x3x+17x−217x+612x−1∣∣ ∣∣=0 is

A
3
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B
0
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C
1
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D
infinite
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Solution

The correct option is C infinite
Given, ∣ ∣x3x+22x12x14x3x+17x217x+612x1∣ ∣=0

Applying R3R33R12R2 we get

∣ ∣x3x+22x12x14x3x+17x23x4x+217x+69x68x12x16x+36x2∣ ∣=0
∣ ∣x3x+22x12x14x3x+1000∣ ∣=0

x has infinite number of solutions.
Hence, option D.

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