The number of real values of x which satisfy the equation xx-1+x=xx-1, is
2
1
Infinite
Zero
Explanation for correct option
The given equation is,
xx-1+x=xx-1
(1) When x>1
xx-1+x=xx-1x=0
So, x=0, doesn't exist.
(2) When 0≤x≤1
x1-x+x=x1-xx=0
(3) When -∞<x<0
-x-x-1-x=x-x-12xx-1-x=02x-x2+xx-1=0x3-x=0
x=0,x=3, does not exist.
Hence, the correct option is B.
Find limx→0 f(x) where f(x) = {x|x|x≠00x≠0