The number of revolutions made by a wheel of diameter $56 c m$ in covering a distance of $1.1 k m$ is $(U s e π = \frac{22}{7})$

31.25

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56.25

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625

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62.5

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Solution

The correct option is C $625$
Diameter $= 56 c m$
Radius $= 28 c m$ (half of diameter)

$1.1 k m = 1, 10, 000 c m$

Then, total distance covered in one revolution $= 2 π r = 2 \times \frac{22}{7} \times 28 c m = 176 c m$

Hence, total no. of revolutions $= \frac{110000}{176} = 625$

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