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Question

The number of roots of the equation, (81)sin2x+(81)cos2x=30 in the interval [0,π] is equal to:

A
3
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B
2
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C
4
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D
8
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Solution

The correct option is B 2
(81)sin2x+(81)1sin2x=30(81)sin2x+81(81)sin2x=30Let (81)sin2x=tt+81t=30t2+81=30tt230t+81=0t227t3t+81=0(t3)(t27)=0t=3,27(81)sin2x=3,3334sin2x=31,334sin2x=1,3sin2x=14,34in [0,π], sinx0sinx=12,32x=π6,5π6,π3,2π3
Number of solutions =4

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