Question

The number of roots of the equation $\sqrt{x-2}(x^2-4x+3)=0$ is

• A. three
• B. four
• C. one
• D. two

Answer 1

The correct option is D two

$\sqrt{x-2}(x^2-4x+3)=0squaringonbothsides,x\ge 2(x-2){(x^2-4x+3)}^2=0(x-2){(x-3)}^2{(x-1)}^2=0\therefore x=1,2,3butasx\ge 2sox=2or3\therefore 2realroots$