The number of roots of the equation xlog3x√x=1 is/are
Substitute log3x=t
The equation becomes
3t2×3t2=1
⇒3t2+t2=1
⇒t2+t2=0
t=0 or t=−12
Each value of t will give one value of x. Hence, there are two solutions.
If α,β and γ are the roots of the equation x3+2x2+3x+1=0. Find the equation whose roots are 1α3,1β3,1γ3