MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sign of Trigonometric Ratios in Different Quadrants

The number of...

Question

The number of roots of the quadratic equation $8 {sec}^{2} θ - 6 sec θ + 1 = 0$

Open in App

Solution

$8 s e c^{2} θ - 6 s e c θ + 1 = 0 L e t s e c θ = t, t h e n 8 t^{2} - 6 t + 1 = 0 8 t^{2} - 4 t - 2 t + 1 = 0 4 t (2 t - 1) - 1 (2 t - 1) = 0 (4 t - 1) (2 t - 1) = 0 ∴ t = 1 / 4 o r 1 / 2 b u t t = s e c θ a n d h e n c e t \geq 1 s o n o s o l u t i o n p o s s i b l e$

Suggest Corrections

thumbs-up

1

Similar questions

The number of roots of the quadratic equation $8 s e c^{2} θ - 6 s e c θ + 1$ = 0 is

Q. Number of roots of the quadratic equation

8 {sec}^{2} x - 6 sec x + 1 = 0

Consider the quadratic equation

(1 + m) x^{2} - 2 (1 + 3 m) x + (1 + 8 m) = 0

m \in R - {- 1})

, then the number of integral values of

^{'} m^{'}

such that given quadratic equation has imaginary roots are,

x_{1}, x_{2},

are the roots of quadratic equation

x^{2} + a x + b = 0

a, b

are complex numbers and

y_{1}, y_{2}

are the roots of the quadratic equation

y^{2} + | a | y + | b | = 0

| x_{1} | = | x_{2} | = 1

Q. Using quadratic formula find the roots of quadratic equation

2 x^{2} - 3 x + 1 = 0

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Trigonometric Functions in a Unit Circle

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Sign of Trigonometric Ratios in Different Quadrants

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon