The number of roots of the quadratic equation 8 2-6 sec -1-0 is

The correct option is B 0 8sec^2 θ 6 sec θ + 1 =0 ⇒ sec θ = 1/2 or, sec θ = 1/4, but sec θ ≥ 1 or sec θ ≤ 1. Hence the given equation has no solution. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Greatest Integer Function

The number of...

Question

The number of roots of the quadratic equation $8 s e c^{2} θ - 6 s e c θ + 1$ = 0 is

Infinite

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
0

8 $s e c^{2} θ - 6 s e c θ + 1$ =0 ⇒ $s e c θ$ = $\frac{1}{2}$

or, $s e c θ$ = $\frac{1}{4}$ , but $s e c θ$ ≥ 1 or $s e c θ$ ≤ -1.

Hence the given equation has no solution.

Suggest Corrections

Similar questions

Q. The number of roots of the quadratic equation

8 {sec}^{2} θ - 6 sec θ + 1 = 0

is:

Q. Number of roots of the quadratic equation

8 {sec}^{2} x - 6 sec x + 1 = 0

is/are:

Q. The roots of the quadratic equation

8 s e c^{2} x - 6 s e c x + 1 = 0

are zero.

Q. Roots of quadratic equation

x^{2} - 5 x + 6 = 0

Q. Quadratic equation whose roots are the number

\frac{1}{10 - \sqrt{72}}

and

\frac{1}{10 + 6 \sqrt{2}}

a x^{2} + b x + c = 0

the the value of

a + b + c

is ?

Join BYJU'S Learning Program

The number of roots of the quadratic equation 8sec2θ−6sec θ+1 = 0 is

The correct option is D 0 8sec2θ−6sec θ+1 =0 ⇒ sec θ = 12 or, sec θ = 14, but sec θ ≥ 1 or sec θ ≤ -1. Hence the given equation has no solution.

The number of roots of the quadratic equation $8 s e c^{2} θ - 6 s e c θ + 1$ = 0 is

The correct option is D
0

8 $s e c^{2} θ - 6 s e c θ + 1$ =0 ⇒ $s e c θ$ = $\frac{1}{2}$

or, $s e c θ$ = $\frac{1}{4}$ , but $s e c θ$ ≥ 1 or $s e c θ$ ≤ -1.

Hence the given equation has no solution.