The number of $S - S$ bonds in polythionic acid $H_{2} S_{n} O_{6}$ is :

n

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n - 1

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n - 2

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none of these

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Solution

The correct option is B $n - 1$
The number of $S - S$ bonds in polythionic acid $H_{2} S_{n} O_{6}$ is $n - 1$ .

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(H_{2} S_{n} O_{6})

(1 + x)^{n} = C_{0} + C_{1} x + C_{2} x^{2} + \dots + C_{n} x^{n},

n \sum r = 0 n \sum s = 0 (r + s) C_{r} C_{s}

(1 + x)^{n} = C_{0} + C_{1} x + C_{2} x^{2} + \dots + C_{n} x^{n},

\sum \sum 0 \leq r < s \leq n (r + s) (C_{r} + C_{s})

S_{n}

U_{n} = \sum_{n = 1}^{n} S_{n}

r S_{n} + (1 - r) U_{n} =

S_{n}

U_{n} = \sum_{n = 1}^{n} S_{n}

r S_{n} + (1 - r) U_{n} =

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