Question

The number of sodium atoms in 4 moles of sodium ferrocyanide $\left(N{a}_3\right[Co\left(N{O}_2{)}_6\right])$ is:
(Consider Avogadro's number = $6\times {10}^{23})$

• A. $4.32\times {10}^{23}$
• B. $2.24\times {10}^{24}$
• C. $9.68\times {10}^{23}$
• D. $7.2\times {10}^{24}$

Answer 1

The correct option is D $7.2\times {10}^{24}$

We know that three sodium atoms are present in sodium ferrocyanide $N{a}_3\left[Co\right(N{O}_2{)}_6]$.
Hence, the total number of $Na$ atoms in 4 moles of $N{a}_3\left[Co\right(N{O}_2{)}_6]$
= number of moles $\times$ number of atom $\times$ Avogadro's number
$=4\times 3\times 6\times {10}^{23}=7.2\times {10}^{24}$