The number of solution of 2cos2-2sin2x-x2-1x2- 0 - x -2 is

The correct option is B Zero 2 ( cos^2 π2 ) ( sin^2x )=x^2+1x^2 #160; =2(0) sin^2x=x^2+1x^2 #160; =x^2+1x^2=0 #160;not possible for any ...

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AM,GM,HM Inequality

The number of...

Question

The number of solution of $2 {cos}^{2} \frac{π}{2} {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}$ is

Zero

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One

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Infinite many

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Four

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{cos}^{2} (\frac{x}{2}) {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

2 {cos}^{2} \frac{x}{2} {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

{cos}^{2} (\frac{x}{2}) {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

2 {cos}^{2} \frac{x}{2} . {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

2 sin 2 x + 2 \sqrt{2} sin (x - \frac{π}{4}) = 1

[0, π]

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