The number of solution(s) of the equation esinx−e−sinx−4=0 is
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Solution
Given, esinx−e−sinx−4=0
Putting esinx=t, we get t−1t−4=0⇒t2−4t−1=0⇒t=4±√202⇒t=2±√5⇒esinx=2±√5
As sinx∈[−1,1]⇒esinx∈[e−1,e]
Now, we know that 2+√5>e2−√5<e−1
So, the given equation has no solution.