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Question

The number of solution(s) of the equationsin(-1)2x - cos(-1)x + tan(-1)2x = pi/2is

(1) Zero (2) One(3) Two (4) Infinitely many

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Solution

12x1x[1,1]2xR

12x121x1xR

x[12,12]

cos1xtan12x=π2sin12x=cos12x

tan12x=cos12x+cos1x

Converting tan1 to cos1,


cos14x2+11=cos1(2x214x21x2)

LHS is always -ve, and RHS is always +ve

cos1x[0,π]

So, number of solution is zero.


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