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Question

The number of solution(s) of the equation sin2x+4x2x+1+1=0 is

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Solution

sin2x+4x2x+1+1=0
(sinx)2+(2x)22.2x+1=0
(sinx)2+(2x1)2=0
This is only possible when
sinx=0 and 2x1=0
sinx=0 and 2x=1
x=0

Hence, the number of solution is 1.


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