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Question

The number of solution(s) of the equation tanxtan4x=1 for 0<x<π is

A
1
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B
2
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C
4
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D
5
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Solution

The correct option is C 4
tanxtan4x=1
cos4xcosxsin4xsinx=0
cos5x=0
5x=(2nπ+)π2,nZ
x=(2n+1)π10;0<x<π
=π10,3π10,π2,7π10,9π10
But for π2, tanx is not defined
Thus, there are 4 solutions only.

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