The number of solution(s) of the equation tanxtan4x=1 for 0<x<π is
A
1
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B
2
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C
4
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D
5
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Solution
The correct option is C4 tanxtan4x=1 ⇒cos4xcosx−sin4xsinx=0 ⇒cos5x=0 ⇒5x=(2nπ+)π2,n∈Z ⇒x=(2n+1)π10;0<x<π =π10,3π10,π2,7π10,9π10
But for π2,tanx is not defined
Thus, there are 4 solutions only.