The number of solutions of the equation x-7x-3-3-7x-3 is

X 7x 3=3 7x 3 For the given equation to be defined, x 3 Now, solving the equation x 7x 3=3 7x 3 ⇒ x = 3 But we cannot take x= 3 as a valid solution. Hence, the ...

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Standard XI

Mathematics

Quadratic Equation

The number of...

Question

The number of solution(s) of the equation $x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$ is

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Solution

The correct option is A $0$
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$
For the given equation to be defined,
$x \neq 3$
Now, solving the equation
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3} \Rightarrow x = 3$
But we cannot take $x = 3$ as a valid solution.
Hence, the given equation has no solution.

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The number of solution(s) of the equation x−7x−3=3−7x−3 is

The correct option is A 0x−7x−3=3−7x−3 For the given equation to be defined, x≠3 Now, solving the equation x−7x−3=3−7x−3⇒x=3 But we cannot take x=3 as a valid solution. Hence, the given equation has no solution.

The number of solution(s) of the equation $x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$ is

The correct option is A $0$
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$
For the given equation to be defined,
$x \neq 3$
Now, solving the equation
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3} \Rightarrow x = 3$
But we cannot take $x = 3$ as a valid solution.
Hence, the given equation has no solution.