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Question

The number of solution(s) of the system of equations x+4yz=0,3x4yz=0 and x3y+z=0 is

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Solution

x+4yz=0
3x4yz=0
x3y+z=0
Δ=∣ ∣141341131∣ ∣
=1(43)4(3+1)1(9+4)
=716+5
Δ=18
Δx=∣ ∣041041031∣ ∣=0
Δy=0,Δz=0
Hence, system of equation has unique solution, i.e., 1 solution.

1098363_1195916_ans_be56174ce21447c0bd7e3ab402479061.jpg

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