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Question

The number of solution(s) of {x}+{x2}+{x3}=3 is
(where {.} denotes fractional part function)

A
2
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B
0
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C
1
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D
3
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Solution

The correct option is B 0
We know that, fractional part function lies in [0,1).

0{x}<1
0{x2}<1
0{x3}<1

Adding the three inequalities, we get
0{x}+{x2}+{x3}<3
Hence, {x}+{x2}+{x3}=3 has no solution.

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