wiz-icon
MyQuestionIcon
MyQuestionIcon
10
You visited us 10 times! Enjoying our articles? Unlock Full Access!
Question

The number of solutions for the equation 2sin1x2x+1+cos1x2x=3π2 is

A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Infinite
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2
2sin1x2x+1+cos1x2x=3π2
For existence of domain of sin1x2x+1
1x2x+110x2x+11x2x0x[0,1]
For cos1x2x
0x2x1x2x0x(x1)0x[,0][1,]
Only two points are common in their domains i.e. 0 and 1 which also satisfies the given equation.
So option B is correct

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 5
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon