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Question
The number of solutions for the system of equations 2x+y=4,3x+2y=2 and x+y=−2 is
The number of solutions for the system of equations 2x+y=4,3x+2y=2 and x+y=−2 is
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Solution
The correct option is A 1
We have three equations: 2x+y=4,3x+2y=2,x+y=−2
Subtracting first from second equation, we get x+y=−2, which is same as the third equation.
Therefore third equation is redundant.
Solving first and second equation, we get x=6,y=−8
Hence, there is only one solution for the system of equations.
We have three equations: 2x+y=4,3x+2y=2,x+y=−2
Subtracting first from second equation, we get x+y=−2, which is same as the third equation.
Therefore third equation is redundant.
Solving first and second equation, we get x=6,y=−8
Hence, there is only one solution for the system of equations.
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