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Question

The number of solutions log(3x2+x2)=3log(3x2) is:

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Solution

log(3x2+x2)=3log(3x2)
3x2+x2=(3x2)3
3x2+x2=(3x)3(2)33(3x)(2)(3x2)
3x2+x2=27x3818x(3x2)
3x2+x2=27x3854x2+36x
27x357x2+35x6=0
therefore3solutionsarepossible
butasx23
thereforeonlytwosolutionsofxarepossible.

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