The number of solutions of 5cos2θ−3sin2θ+6sinθcosθ=7 in the interval [0,2π] is
A
2
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B
4
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C
0
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D
1
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Solution
The correct option is C0 The equation can be rewritten as 5(1+cos2θ2)−3(1−cos2θ2)+3sin2θ=7 ⇒4cos2θ+3sin2θ=6 But4cos2θ+3sin2θ≤5 So, there is no solution for the given equation.