The number of solutions of $^{61} C_{n + 1} =^{61} C_{2 n - 1}$ is

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Solution

The correct option is C 1
Given, $^{61} C_{n + 1} =^{61} C_{2 n - 1}$
$n + 1 = 2 n - 1 o r n + 1 = 61 - (2 n - 1)$
$=> n = 2 o r n = \frac{61}{3}$
$∴ n$ has one solution as n can not be fraction.

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