wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of solutions of sin7x+cos7x=1, x[0,4π] is equal to:

A
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5
sin7x+cos7x=1
As sin7x+cos7xsin2x+cos2x1
The equation gives solution only when one of sinx,cosx is unity and other vanishes.
i.e., x=0, π2,2π,5π2,4π

flag
Suggest Corrections
thumbs-up
81
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon