The number of solutions of sin7x+cos7x=1,x∈[0,4π] is equal to:
A
5
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B
7
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C
11
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D
9
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Solution
The correct option is A5 sin7x+cos7x=1
As sin7x+cos7x≤sin2x+cos2x≤1
The equation gives solution only when one of sinx,cosx is unity and other vanishes.
i.e., x=0,π2,2π,5π2,4π