The number of solutions of tan2x−sec8x+1=0 in (0,12) is:
A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D3 The equation is tan2x−sec8x+1=0 Now, tan2x=sec2x−l On substituting sec2x−l−sec8x+1=0 sec2x(1−sec6x)=0 sec6x=1 (sec3x)2=1 secx=±1 Solutions are π,2π,3π 0 is not included in the range and 4π>12 Therefore there are only 3 solutions