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Question

The number of solutions of the equation 16(sin5x+cos5x)=11(sinx+cosx) in the interval [0,2π] is

A
6
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B
7
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C
8
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D
9
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Solution

The correct option is A 6
16(sin5x+cos5x)=11(sinx+cosx)=0(sinx+cosx){16(sin4xsin3xcosx+sin2xcos2xsinxcos3x+cos4x)11}=0(sinx+cosx){16(1sin2xcos2xsinxcosx)}11=0(sinx+cosx)(4sinxcosx1)(4sinxcosx+5)=0As4sinxcosx+50,Wehavesinx+cosx=0,4sinxcosx1=0therequiredvaluesareπ12,5π12,9π12,13π12,17π12,21π12,THEYARE6SOLUTIONSON[0,2π]

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