Question

The number of solutions of the equation,$2{\left\{x\right\}}^2+5\left\{x\right\}-3=0$ is

• A. No solution
• B. $1$
• C. $2$
• D. Infinite

Answer 1

The correct option is C $2$

We have,

$2{\left\{x\right\}}^2-5\left\{x\right\}-3=0$

$2x^2+5x-3=0$

$\Rightarrow 2x^2+(6-1)x-3=0$

$\Rightarrow 2x^2+6x-1x-3=0$

$\Rightarrow 2x(x+3)-1(x+3)=0$

$\Rightarrow (x+3)(2x-1)=0$

If $2x-1=0$

$x=\frac{1}{2}$

If

$x+3=0$

$x=-3$

Hence, this is the answer.