wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of solutions of the equation [3x][x+1]=3x, where [.] denotes greatest integer function, is equal to

Open in App
Solution

[3x][x+1]=3x
[x+1]=3x[3x]
[x+1]={3x}
where {.} denotes fractional integer function
Now, 0{3x}<1
[x+1]=0[x+1]=0
0x+1<1
1x<033x<0
[3x]=3, 2, 1
Now,
[3x]0=3x
3x=3, 2, 1
x=33, 23, 13
x=1, 23, 13

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon