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Question

The number of solutions of the equation 3sin2x7sinx+2=0 in the interval [0,5π] is?

A
0
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B
5
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C
6
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D
10
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Solution

The correct option is C 6
We have, 3sin2x7sinx+2=0
(3sinx1)(sinx2)=0
sinx=13 [sinx20]
x=sin113,πsin113,2π+sin113,3πsin113,4π+sin113,5πsin113.

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