The number of solutions of the equation 3sin2x−7sinx+2=0 in the interval [0,5π] is?
A
0
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B
5
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C
6
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D
10
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Solution
The correct option is C6 We have, 3sin2x−7sinx+2=0 ⇒(3sinx−1)(sinx−2)=0 ⇒sinx=13[∵sinx−2≠0] ⇒x=sin−113,π−sin−113,2π+sin−113,3π−sin−113,4π+sin−113,5π−sin−113.