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Question

The number of solutions of the equation x(logx+74)=10logx+1 is

A
zero
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B
1
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C
2
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D
none of these
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Solution

The correct option is C 2
x(logx+7)4=10logx+1
taking log both sides we get
(logx+74)logx=(logx+1)let logx = t, x>o(as domain of log is greater than 0)
(t+74)t=t+1t2+7t=4t+4t2+3t4=0(t+4)(t1)=0t=1 or 4t=1log x = 1x=101x=10,t=4 log x = 4x=104x=1104 so 2 solutions of x

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