wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of solutions of the equation
[sinx]=cosxx[0,2π] (where [] denotes the greatest integer function)

A
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0
cosx=[sinx]
cosx=1,0,1 as 1cosx1
x=π.π/2.2π[sinx]=0,1,0
so equation [sinx]=cosx has no solution
Thus option B is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Some Functions and Their Graphs
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon