The number of solutions of the equation: m2=1614+n2, where both m and n are integers, is:
Let x and y be consecutive integers. Suppose m be the number of solutions of x3−y3=3k2 and n be the number of solutions of x3−y3=2t2 , where k, t are integers. Then m + n equals:
If limx→2 (xn)−(2n)x−2 =80 , where n is a positive integer, then n=
The value of limn→∞[n1+n2+n4+n2+n9+n2+⋯+12n] is equal to [Bihar CEE 1994]