The number of solutions of the equation- sin 5x-cos 5x- 1-cos x-1-sin x sin x-cos x is-

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The number of...

Question

The number of solutions of the equation, ${sin}^{5} x - {cos}^{5} x = \frac{1}{cos x} - \frac{1}{sin x} (sin x \neq cos x)$ is:

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infinite

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none of these

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\frac{sin 5 x - 2 sin 3 x + sin x}{cos 5 x - cos x}

{sin}^{5} x - {cos}^{5} x = \frac{1}{cos x} - \frac{1}{sin x}

sin x \neq cos x)

\frac{sin 5 x - 2 s i n 3 x + sin x}{cos 5 x - cos x} = tan x

\frac{s i n x - s i n 3 x + s i n 5 x - s i n 7 x}{c o s x - c o s 3 x - c o s 5 x + c o s 7 x} = c o t 2 x

16 (s i n^{5} x + c o s^{5} x) = 11 (s i n x + c o s x)

[0, 2 π]

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