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Byju's Answer
Standard XII
Mathematics
General Solution of sin theta = sin alpha
The number of...
Question
The number of solutions of the equation
sin
(
π
x
2
√
3
)
=
x
2
−
2
√
3
x
+
4
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Solution
sin
(
π
x
2
√
3
)
=
x
2
−
2
√
3
x
+
4
M
i
n
v
a
l
u
e
o
f
R
H
S
i
s
4
a
c
−
b
2
4
a
=
4
(
1
)
(
4
)
−
(
2
√
3
)
2
4
(
1
)
=
1
w
h
i
c
h
o
c
c
u
r
s
a
t
x
=
−
b
2
a
=
2
√
2
2
=
√
3
O
n
t
h
e
o
t
h
e
r
h
a
n
d
,
L
.
H
.
S
=
sin
(
π
2
√
3
)
h
a
s
max
.
v
a
l
u
e
1
∴
L
.
H
.
S
≤
1
a
n
d
R
.
H
.
S
≥
1
⇒
L
H
S
=
R
H
S
=
1
w
h
i
c
h
i
s
p
o
s
s
i
b
l
e
o
n
l
y
w
h
e
n
x
=
√
3
∴
T
h
e
r
e
i
s
o
n
l
y
o
n
e
r
e
a
l
s
o
l
u
t
i
o
n
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General Solution of sin theta = sin alpha
Standard XII Mathematics
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