The number of solutions of the equation $(| sin x | - 1) (5 | sin x | - 1) = 0$ in $[0, 2 π]$ is

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $6$
$(| sin x | - 1) (5 | sin x | - 1) = 0$
$\Rightarrow | sin x | = 1 or | sin x | = \frac{1}{5}$
So, plotting the graphs of $y = | sin x |, y = 1, y = \frac{1}{5}$

$∴$ From the above graph, we conclude that the total number of solutions of the given equation is $6.$

Suggest Corrections

Similar questions

| cot x | = cot x + \frac{1}{sin x}

x \in [0, 2 π]

| sin x | = sin x + 2 cos x

[0, 2 π]

2 s i n^{3} + 6 s i n^{2} x - s i n x - 3 = 0

(0, 2 π)

| cot x | = c o t x + \frac{1}{s i n x}

[0, 2 π]

{cos}^{2} x + sin x + 1 = 0, x \in [0, 2 π]

Join BYJU'S Learning Program