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Question

The number of solutions of the equation 1sinx=cosx in the interval [0,3π] is

A
2
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B
4
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C
5
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D
6
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Solution

The correct option is B 4
1sinx=cosx (1)
1sinx=cos2x
sinx(sinx1)=0
sinx=0 or sinx=1
x=0,π,2π,3π or x=π2,5π2

But x=π,3π do not satisfy equation (1).
Total number of solutions is 4.

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