The number of solutions of the equation; $x^{3} + 2 x^{2} + 5 x + 2 cos x = 0$ in $[0, 2 π]$ is

0

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1

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Solution

The correct option is A $0$

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Similar questions

x^{3} + 2 x^{2} + 5 x + 2 c o s x = 0

[0, 2 π]

x^{3}

x^{2}

π

∣ ∣ 2 x^{2} - 5 x + 3 ∣ ∣ + (x - 1) = 0

(2 \cos x + 1) (4 \cos x + 5) = 0

2 cos x = 2 x^{2} + 1

x \in [- \frac{π}{2}, \frac{π}{2}]

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