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Question

The number of solutions of the equation x3+2x2+5x+2cosx=0 in [0,2π] is

A
\N
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B
1
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C
2
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D
3
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Solution

The correct option is A \N


Solution : x3+2x2+5x+2cosx=0
x3+2x2+5x=2cosx
y=x(x2+2x+5)=2cosx
y=x(x2+2x+5)
if x[0,2π] then number of solution is zero.


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