Question

# The number of solutions of the equation $$x^3+x^2+4x+2 \sin x =0$$ in $$0\leq x \leq 2\pi$$ is-

A
Zero
B
One
C
Two
D
Four

Solution

## The correct option is B One$$x^3+x^2+4x+2 \sin x =0$$ Only $$x=0$$ satisfies the above equation.Hence, there is one solution.Maths

Suggest Corrections

0

Similar questions
View More

People also searched for
View More