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Question

The number of solutions of the equation $$x^3+x^2+4x+2 \sin x =0$$ in $$0\leq x \leq 2\pi$$ is-


A
Zero
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B
One
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C
Two
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D
Four
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Solution

The correct option is B One
$$x^3+x^2+4x+2 \sin x =0$$ 
Only $$x=0$$ satisfies the above equation.
Hence, there is one solution.

Maths

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