The number of solutions of the equation $x^{3} + x^{2} + 4 x + 2 sin x = 0$ in $0 \leq x \leq 2 π$ is-

Zero

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One

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Two

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Four

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Solution

The correct option is B One
$x^{3} + x^{2} + 4 x + 2 sin x = 0$
Only $x = 0$ satisfies the above equation.
Hence, there is one solution.

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