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Question

The number of solutions of the equation z2+|z|2=0, where zC is?

A
One
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B
Two
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C
Three
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D
Four
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Solution

The correct option is B Two
Let z=x+iyz2=x2y2+2xyi
|z|=x2+y2|z|2=x2+y2x2y2+2xyi+x2+y2=02x2+2xyi=02x(x+yi)=0x=0orx=yi
2 Solutions.

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