. The number of solutions of the equations of $2 x + 5 y = 11$ , $6 x + 15 y = 1$ are

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Solution

The correct option is D 0
Consider the first equation
$2 x + 5 y = 11$ ...(i)
Consider the second equation
$6 x + 15 y = 1$
$\Rightarrow 2 x + 5 y = \frac{1}{3}$ ...(ii)
Hence both i and ii are equations of parallel lines.
Therefore they never intersect and hence do not have any solution.

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The following pairs of linear equations 2x + 5y = 3 and 6x + 15y = 12 represent :

2 x + 5 y = - 11 a n d 5 x + 15 y = - 44

2 x + 5 y = - 11

5 x + 15 y = - 44

2 x + 5 y = k, k x + 15 y = 18

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