The number of solutions to tan x +sec x =2 cos x in (0,2π) is
A
2
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B
3
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C
1
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Solution
The correct option is B 3 The given equations is tan x +sec x =2 cos x ⇒sinx+1=2cos2x⇒sinx+1=2(1−sin2x)⇒2sin2x+sinx−1=0⇒(2sinx−1)(sinx+1)=0⇒sinx=12,−1⇒x=30∘,150∘,270∘