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Question

The number of solutions (x,y) of the equation 1+x2+2xsin(cos1y)=0, are

A
4
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B
3
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C
2
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D
1
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Solution

The correct option is C 1
For given equation to hold true when x=1,y=0
So, Putting these values in the Equation :- 1+x2+2xsin(cos1y)=0
1+1221sin(cos1(0))=1+1221sin(3π2)=1+12=0

Hence, only 1 solution is possible

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