The number of spherical lead shots each 4.2 cm in diameter that can be obtained from a rectangular solid with diameter 66 cm x 42 cm x 21 cm is

750

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3000

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1500

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None of the above

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Solution

The correct option is C 1500
Number of shots = $\frac{v o l u m e o f c u b o i d}{v o l u m e o f s p h e r e}$

= $\frac{66 \times 42 \times 21}{\frac{4}{3} \times \frac{22}{7} \times \frac{21}{10} \times \frac{21}{10} \times \frac{21}{10}} = 1500$

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Similar questions

Q. How many spherical lead shots of diameter

4.2

cm can be obtained from a solid rectangular lead piece with dimensions

66

\times

42

\times

21

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Question 11
How many spherical lead shots each of diameter 4.2 cm can be obtained from a solid rectangular lead piece with dimensions 66 cm, 42 cm and 21 cm.

Question 11
How many spherical lead shots each of diameter 4.2 cm can be obtained from a solid rectangular lead piece with dimensions 66 cm, 42 cm and 21 cm.

Q. How many spherical lead shots each

4.2 c m

in diameter can be obtained from a rectangular solid (cuboid) of lead with dimensions

66 c m, 42 c m, 21 c m

. (Take

π = \frac{22}{7}

)

How many spherical lead shots each of diameter 4.2 cm can be obtained from a solid rectangular lead piece with dimensions $6 c m \times 42 c m \times 21 c m$ .

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The number of spherical lead shots each 4.2 cm in diameter that can be obtained from a rectangular solid with diameter 66 cm x 42 cm x 21 cm is

The correct option is C 1500Number of shots = volumeofcuboidvolumeofsphere = 66×42×2143×227×2110×2110×2110=1500

The correct option is C 1500
Number of shots = $\frac{v o l u m e o f c u b o i d}{v o l u m e o f s p h e r e}$

= $\frac{66 \times 42 \times 21}{\frac{4}{3} \times \frac{22}{7} \times \frac{21}{10} \times \frac{21}{10} \times \frac{21}{10}} = 1500$