The number of stereoisomer possible for the following compound is:
$C H_{3} - C H = C H - C H (B r) - C H_{2} - C H_{3}$

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Solution

The correct option is C 4

There are 2 stereogenic areas so there are $2^{2} = 4$ stereoisomers possible for this structure.

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Similar questions

C H_{3} - C H = C H - C H (O H) - C H_{3}

C H_{3} C H = C H - C H = C H - C H = C H - C l

The number of stereoisomers possible for a compound of the molecular formula CH₃—CH=CH—(CHCl)—Me is:

C H_{3} - C H_{2} - C H = C H - C H B r - C H = C H - C H_{2} - C H_{3}

C H_{3} - C H = C H - C H_{3}

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