Question

The number of stereoisomers possible for $H_{3}C-CH\left(OH\right)-CH\left(OH\right)-C{H}_3$ is :

• A. 1
• B. 2
• C. 6
• D. 4

Answer 1

Answer: (C)

6

The number of stereoisomers possible for $H_{3}C-CH\left(OH\right)-CH\left(OH\right)-C{H}_3$ is 3.

$H_{3}C-CH\left(OH\right)-CH\left(OH\right)-C{H}_3$ has two chiral carbon atoms and is symmetrical, therefore n=2

Number of d and l isomers $2^{n-1}=2^{2-1}=2$

Number of meso forms $2^{n/2-1}=2^{2/2-1}=2^2=4$

Total number of stereoisomers $=2+4=6$

Hence, the correct option is $C$